Big Idea: Many important practical and mathematical applications involve comparing quantities of one kind or another; it is important to know which method to use and how we should use them Problem 4.2 Using Unit Rate
Madeline's car went 580 miles with 19 gallons of gas.
Luis's car went 452 miles with 15.5 gallons of gasoline. A: For each car. find a unit rate describing the mileage. Which Car got better gas mileage? In other words, which car went more miles per gallon of gas Ans: Madeline's car has better gas mileage than Luis's car. This is because Madeline's car can go 30 miles per gallon and Luis's car can go only 29 miles per gallon. B: Complete a table like the one below, showing the fuel used and the miles covered by each car based on the unit rates you found in part A. We call this kind of table a rate table.
Ans. C: Look at the patterns in your table. For each car, write an equation for a rule you can use to predict the miles driven (m) from the gallons of gas used (g).
Ans. Madeline's car: M=30g, Luis's car: M:29g D: Use the Rules you wrote in part C to find the number of miles each car could cover if it used 9.5, 15.5, 19, 23.8, 100, 125 and 150 gallons of gasoline.
Ans. Madeline's car can go 285 miles with 9.5 gallons of gas, 465 miles with 15.5 gallons of gas, 570 miles with 19 gallons of gas, 714 miles with 23.8 gallons of gas, 3000 miles with 100 gallons of gas, 3750 miles with 125 gallons of gas and 4500 miles with 150 gallons of gas.
Luis's car can go 275.5 miles with 9.5 gallon of gas, 449.5 miles with 15.5 gallons of gas, 551 miles with 19 gallons of gas, 690.2 miles with 23.8 gallons of gas, 2900 miles with 100 gallons of gas, 3625 miles with 125 gallons of gas and 4350 with 150 gallons of gas.
Follow-ups 1.Use your data from B or D to sketch graphs of (gallons, miles) data for each car. Ans.
Madeline's car:
Luis's car:
2. How are your two graph alike? How are they different? Ans. The two graphs are similar because they both are increasing with constant rate. The difference is that it is a different constant rate 3. What do you think makes the two graphs different?
Ans. I think the rate of the graph makes the two graphs different.
Block D
30/11/09
Comparing and Scaling
Big Idea: Many important practical and mathematical applications involve comparing quantities of one kind or another; it is important to know which method to use and how we should use themProblem 4.2 Using Unit Rate
Madeline's car went 580 miles with 19 gallons of gas.
Luis's car went 452 miles with 15.5 gallons of gasoline.
A: For each car. find a unit rate describing the mileage. Which Car got better gas mileage? In other words, which car went more miles per gallon of gas
Ans: Madeline's car has better gas mileage than Luis's car. This is because Madeline's car can go 30 miles per gallon and Luis's car can go only 29 miles per gallon.
B: Complete a table like the one below, showing the fuel used and the miles covered by each car based on the unit rates you found in part A. We call this kind of table a rate table.
Ans.
C: Look at the patterns in your table. For each car, write an equation for a rule you can use to predict the miles driven (m) from the gallons of gas used (g).
Ans. Madeline's car: M=30g, Luis's car: M:29g
D: Use the Rules you wrote in part C to find the number of miles each car could cover if it used 9.5, 15.5, 19, 23.8, 100, 125 and 150 gallons of gasoline.
Ans. Madeline's car can go 285 miles with 9.5 gallons of gas, 465 miles with 15.5 gallons of gas, 570 miles with 19 gallons of gas, 714 miles with 23.8 gallons of gas, 3000 miles with 100 gallons of gas, 3750 miles with 125 gallons of gas and 4500 miles with 150 gallons of gas.
Luis's car can go 275.5 miles with 9.5 gallon of gas, 449.5 miles with 15.5 gallons of gas, 551 miles with 19 gallons of gas, 690.2 miles with 23.8 gallons of gas, 2900 miles with 100 gallons of gas, 3625 miles with 125 gallons of gas and 4350 with 150 gallons of gas.
Follow-ups
1.Use your data from B or D to sketch graphs of (gallons, miles) data for each car.
Ans.
Madeline's car:
Luis's car:
2. How are your two graph alike? How are they different?
Ans. The two graphs are similar because they both are increasing with constant rate. The difference is that it is a different constant rate
3. What do you think makes the two graphs different?
Ans. I think the rate of the graph makes the two graphs different.